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Math Write an equation of the tangent function with period (3π)/8, phase shift π/5, and vertical shift 2 Ex 56, 9 If x and y are connected parametrically by the equations without eliminating the parameter, Find 𝑑𝑦/𝑑𝑥, 𝑥=𝑎 sec ⁡𝜃, 𝑦=𝑏 tan⁡𝜃Here 𝑑𝑦/𝑑𝑥 = (𝑑𝑦/𝑑𝜃)/ (𝑑𝑥/𝑑𝜃) Calculating 𝒅𝒚/𝒅𝜽 𝑑𝑦/𝑑𝜃 = 𝑑 (𝑏 tan⁡𝜃 )/𝑑𝜃 𝑑𝑦/𝑑𝜃 = 𝑏Obtain the solution (3tan x2cos y) sec^2x dx tan x sin y dy = 0 fullscreen Expand

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If y=sec(sqrt(tan x)) then find (dy)/(dx)-I can hardly make sense of this, but maybe I should put Having solved the de, I see that if I had started by dividing by x, the equation would then have become exactThe derivative of sec x with respect to x is written as d/dx(sec x) and it is equal to sec x tan x Let us learn more about the differentiation of sec x along with its formula, proof by different methods, and a few solved examples Then, sec y = x (1) Differentiating both sides with respect to x, sec y tan y (dy/dx) = 1 dy/dx = 1

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 Find the general solution of the differential equation $\frac{dy}{dx}\tan x\tan y=\cos x\sec y$ My try $\frac{dy}{dx}\tan x\tan y=\cos x\sec y$ $\implies \frac{dyAnswer (1 of 4) tan y = sin x Differentiating implicitly wrt x sec^2 y dy/dx = cos x dy/dx = cos x / sec^2 y tan y = sin x tan^2 y = sin^2 x tan^2 y 1 = sin^2 If dy/dx = tan (x), then y= A) 1/2 (tan x)^2 CB) (sec x)^2 CC) lnsec x CD) lncos x CE) sec x tan x C If dy/dx = tan (x), then y= A) 1/2 (tan x)^2 C B) (sec x)^2 C C) lnsec x C D) lncos x C E) sec x tan x C 2

Solution for sec y x tan y dy 1 tan y Q Determine whether the sequence defined as follows has a limitIf it does, find the limit (If an an A Let {an} be a real sequence and L be a real number then limit of this sequence {an} = L iff an tendsSolution Verified by Toppr Correct option is B) Given,y=tan −1(secxtanx) ⇒y=tan −1tan( 4π 2x ) ∵tan( 4π 2x )=secxtanx ⇒y= 4π 2x On differentiating wrt x we get dxdy =0 21 = 21 Video Explanation Solve any question of Continuity and Differentiability with Patterns of problems > Was this answer helpful? Learn how to differentiate y=ln (secxtanx) in this video Alternatively, you can use these workings ln(secx tanx) = y ey = secx tanx ey ⋅ dy dx = secxtanx sec2x ey ⋅ dy dx = secx(secx tanx) dy dx = secx(secx tanx) ey dy dx = secx(secx

 Get an answer for 'If tan(xy)=x, then determine dy/dx' and find homework help for other Math questions at eNotesLet y = sec^2 x Let sec x = t Then y = t^2 This implies dy/dt = 2t = 2 sec x t = sec x implies dt/dx = sec xtan x So dy/dx = (dy/dt)×(dt/dx) = 2sec x sec x tan x = 2 sec^2 x tan xIf y=sec(tan^1x) then dy/dx # School If y=sec(tan^1x) then dy/dx Post Answer Answers (1) D Deependra Verma Solution We have , Then , Similar Questions An Unbiased coin is tossed 4 times What is the Probability of getting (i) 3 heads Q If (a – b c) (b – c 2d) (2a c – d

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Given y = sec x o We know π radian = 180 degree x o = (π/180)x radians So y = sec (π/180)x dy/dx = sec (π/180)x tan (π/180)x (π/180) = (π/180) sec x If y = sec(tan^1x), then dy/dx at x = 1 is equal to asked in Limit, continuity and differentiability by Vikky01 (418k points) differentiation;Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutor

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In this problem we have been given that divided by dx That is 10 x And we have to determine the value of Y So in order to get the value of Y, let's take Dx to the other side and let's integrate both sides And upon integration we observe that integration of divide that's just why and integration of 10 X That is log of mud psychics And there will also come a constant C What is the equation of a curve passing through (0, 1) and whose differential equation is given by `dy = y tan x `y = sec x` D `y = "cosec" x` If dy = ( sec x y) / tan x ) dx, then the curve is In a company's parking area, the number of bikes to that of cars are in the ratio 7 5

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If y = tan1 ( sec x tan x) , then (dy/dx) = Q If y = tan−1(secx − tanx), then dxdy = 41 COMEDK COMEDK 07 Continuity and Differentiability Report Error A 2 B −2 C 21 D −21 Solution y = tan−1(secx− tanx) ⇒ dxdy = 1(secx−tanx)21(secx× tanx− sec2x) = 1sec2xtan2x−2secxtanxsecx(tanx−secx) = 2sec2x−2secxtanxsecx(tanx−secx)Use the chain rule to show that, if y = sec (x), then dy/dx = sec (x)tan (x) First, write y in terms of cos (x) We are familiar with cos (x) and know how to differentiate it We know that sec (x) = 1/cos (x) = (cos (x)) 1 Next, find dy/dx in terms of cos (x) and sin (x)If y=x^lnx tan^1x then find (dy)/(dx) at x=1

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Dx d (tan x) = sec²x dx d (cot x) = –cosec²x dx One condition upon these results is that x must be measured in radians Applying the Chain Rule The chain rule is used to differentiate harder trigonometric functions Example Differentiate cos³x with respect to x Let y = cos³x Let u = cos x therefore y = u³ dy = 3u² du du = sin xIf sin y = x sin(ay) , then dy/dx =?How do you solve the math (x sin y/xy cos y/ x) dx x cos (y/x) dy =0?

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For y to be defined x 2 1 x 2 < 1 which is true for all x ∈ R Now , y = sin 1 x 2 1 x 2 ⇒ x 2 1 x 2 = sin y ⇒ x = sin y 1 sin ySee the answer See the answer See the answer done loading Show transcribed image text Expert Answer Who are the experts? If y = sec x tan x, find dy/dx Stepbystep explanation We have y = ( secx tanx ) We have y = ( secx tanx )Now differentiate both sides with respect to x

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Free implicit derivative calculator implicit differentiation solver stepbystepDy/dx = cos^2(xy) – y / x Answer 3 d/dx (tan u) = sec^2 u du/dx So d/dx (tan xy) = sec^2 (xy) x dy/dx y So sec^2(xy) x dy/dx y = dx/dx = 1 sec^2(xy) x dy/dx = 1 – y sec^2(xy) dy/dx = 1 – y sec^2(xy) /x sec^2(xy) Conclusion Above is the solution for "If tan(xy) = x, then dy/dx =" We hope that you find a good5 (3) (3) (0) Choose An Option That Best Describes Your Problem Answer not in Detail

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 Solved Given, y=\tan(\sin^{1}x) then find \frac{dy}{dx} Solve your problem for the price of one coffee Available 24/7 Math expert for every subjectIf `y="sec"(tan^(1)x),` then `(dy)/(dx)` at `x=1` is equal to `1/(sqrt(2))` (b) `1/2` (c) 1 (d) `sqrt(2)` asked in Differentiation by VaibhavNagar ( 933k points) class12Find dy/dx y=sec(tan(x)) Differentiate both sides of the equation The derivative of with respect to is Differentiate the right side of the equation Tap for more steps Differentiate using the chain rule, which states that is where and Tap for more steps To apply the Chain Rule, set as

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Answer (1 of 3) An easy way is to use logarithmic differentation ln y = (sex x) ln (x) Differentiating wrt x, we get (1/y) (dy/dx) = (sec x)(tan x) (ln xBooks Physics NCERT DC Pandey Sunil Batra HC Verma Pradeep Errorless Chemistry NCERT P Bahadur IITJEE Previous Year Narendra Awasthi MS Chauhan Biology Draw graph of y = sec x and find the period Follow Us Popular Chapters by Class Class 6 Algebra BasicIf y = tan x^tan x^tan x, then dy/dx is Get the answer to this question and access a vast question bank that is tailored for students Login 1/tan x log tan x) dy/dx = y log y sec 2 x (1 log (tan x) 1/tan x log tan x) Was this answer helpful?

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X and y be two variables such that x > 0 and xy = 1, then the minimum value of (x y) is Q7 If the tangent of the curve x = at2, y = 2at is perpendicular to xaxis, then its point of contact is Best answer Given, xy = yx Taking logarithm on both sides, we get y log x = x log y Differentiating both sides, wrt x y (1/x) log x (dy/dx) = x (1/y) (dy/dx) log y 1 (y/x) (log x) (dy/dx) = (x/y) (dy/dx) log y (dy/dx) log x (x/y) = log y (y/x) (dy/dx) (y log x Calculate the following integral ∫ sec^4 (3x)/ tan^3 (3x) dx For this one, can I bring up the tan to tan^3?

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Statistics Arithmetic Mean Geometric Mean Quadratic Mean Median Mode Order Minimum Maximum Probability MidRange Range Standard Deviation Variance Lower Quartile Upper Quartile Interquartile Range Midhinge Standard Normal Distribution PhysicsIf y = etan x (log x)tan x then find dy/dx Mathematics and Statistics Advertisement Remove all ads Advertisement Remove all ads Differentiating w r t x, we get `1/u (du)/dx=sec^2x` `therefore (du)/dx=usec^2x` `therefore (du)/dx=e^(tanx)sec^2x` (ii) v = (log x) tan x102 views View upvotes Submission accepted by Vishwajeet Gupta Answer requested by Vishwajeet Gupta 9 2 Share Related Answer Aravind Kumar Worked at CUMMINS India Limited (12–12) 1y 1 tan 2 ⁡ y = sec ⁡ x (x tan

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Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreIt is given that x = tan y To determine the derivative `dy/dx` , use implicit differentiation 1 = `sec^2 y*(dy/dx)` => `dy/dx = 1/(sec^2 y)` => `dy/dx = 1/(1 tan^2y)` => `dy/dx = 1/(1 x^2)`Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries

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To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW If `x^y=y^x`,then find` dy/dx`Click here👆to get an answer to your question ️ If y = sec √(x) , Then find dydx Solve Study Textbooks Join / Login >> Class 12 >> Maths >> Differential Equations >> Introduction to Differential Equations >> If y = sec √(x) , Then find dydx QuestionSolution y = (secx−tanxsecxtanx ) = 1−sinx1sinx ⇒ y = 1−sin2x(1sinx)2 = cos2x1sin2x2sinx ⇒ y = sec2x tan2x2tanxsecx ⇒ y = (secx tanx)2 Now Differentiating (i) wrt x, we get (i) dxdy = 2(secx tanx)secxtanx sec2 x = 2secx(secx tanx)(secxtanx) = 2secx(secx tanx)2

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Then to find y, both sides should be integrated with respect to x, so that ∫(1/y)dy = ∫(sec x)^2 dx The integral of 1/y with respect to y is ln y, the natural logarithm of y, and and the integral of (sec x)^2 with respect to x is tanx Also, an arbitrary constant must be added The resultant equation isLog y = cot x log (tan x)যদি y = (tan x)^(cot x) " then " (dy)/(dx)= ? Transcript Ex 96, 4 For each of the differential equation given in Exercises 1 to 12, find the general solution sec = 0 < 2 Differential equation is of the form Py = Q where P = sec x and Q = tan x Finding integrating factor, IF = IF = e sec IF = e sec tan IF = sec x tan x Solution is y (IF) =

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